Answer:
the first and second option
Step-by-step explanation:
Answer:
The mean value theorem is valid if f(x) is continuous in the interval (0,3) and differentiable in the interval (0,3), the problem is that f(x)=2−|4x−2| is not differentiable in x = 1/2 because 4*1/2 - 2 = 0 and the function |x| is not differentiable in x = 0.
f'(x) = (-4)*(4x−2)/|4x−2|
f(3) = 2−|4*3−2| = 8
f(0) = 2−|4*0−2| = 0
Replacing in f'(c) = f(3)−f(0)/(3−0)
(-4)*(4c−2)/|4c−2| = (8 - 0)/3
(-4)*(4c−2)*3/8 = |4c−2|
-3/2*4c + 3/2*2 = |4c−2|
-6c + 3 = |4c−2|
That gives us two options
-6c + 3 = 4c−2
5 = 10c
1/2 = c
or
6c - 3 = 4c−2
-1 = -2c
1/2 = c
But f'(1/2) is not defined, therefore there is no value of c such that f(3)−f(0)=f'(c)(3−0).
23x = -3x^2 + 8
3x^2 + 23x - 8 = 0
3x^2 + 24x - x - 8 = 0
3x (x + 8) -1 (x + 8) = 0
(x + 8) (3x - 1) = 0
x = -8 or x = 1/3
Answer:
First Option (-4,-3)
Step-by-step explanation:
x+2y=-10
-y=3x+15
-4+2(-3)=-10
-10=-10
-3=3(-4)+15
-3=-3
The answer to this math question is that the tree would be 13.5 meters since you convert the feet to meters
