<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION:
</u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y = 
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.
Number of pounds of cashews is 36 pounds and number of pounds of walnuts is 4 pounds.
Step-by-step explanation:
- Step 1: Given details are cost of cashews = $1.58, cost of walnuts = 78 cents = $0.78, total weight of nuts = 40 pounds, cost of nuts per pound = $1.50
- Step 2: Let number of pounds of cashews to be mixed be C, then number of pounds of walnuts will 40 - C. Form equation with these variables.
⇒ 1.58 C + (40-C) 0.78 = 40 × 1.50
⇒ 1.58 C + 31.2 - 0.78 C = 60
⇒ 1.58 C - 0.78 C = 60 - 31.2
⇒ 0.8 C = 28.8
⇒ C = 36 pounds
- Step 3: Calculate number of pounds of walnuts
⇒ Number of pounds of walnuts = 40 - C = 4 pounds
I’m pretty sure the answer would be 116