3 years ago

A small point deduction applies if a participation activity's question is not answered correctly the first time?

Mathematics

1 answer:

LiRa [457]3 years ago

3 0

Answer: False

Step-by-step explanation:

There is no such deduction when a participation's questions are not answered correctly the first time. Whatever answer is given is part of the learning curve and ensures that the activity can be improved upon.

Had there been a small point deduction then there would be no opportunity to learn because there would be too much fear associated with the wrong answer.

You might be interested in

How to sovle <br> (x+1/x)^2

Slav-nsk [51]

$(\frac{x + 1}{x} ) ^{2} \\ = \frac{ {(x + 1)}^{2} }{ {x}^{2} } \\ = \frac{ (x + 1)(x + 1) }{ {x}^{2} } \\ = \frac{ {x}^{2} + 2x + 1}{ {x}^{2} }$

Hope you could get an idea from here.

Doubt clarification- use comment section.

4 0

3 years ago

Mr. van der westhuizen wants to visit his grandchildren In France. he has heard that it is very expensive for South Africans to

Tomtit [17]

Answer:

u got it right

Step-by-step explanation:

3 0

3 years ago

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

MakcuM [25]

Answer:

A=8.4063 $u^{2}$

Step-by-step explanation:

Be the functions:

$y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7$

according the graph:

$\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}$