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3 years ago

ASAP PLS HELP!!!

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

Answer:

4(-7)

Step-by-step explanation:

Natali [406]3 years ago

3 0

I believe it’s (4,-7)

I think lol

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A certain forest covers an area of 4000km^2. Suppose that each year this area decreases by 3.5%. What will the area be after 9 y

kaheart [24]

Simply will say
4000(3.5%) = 140 km^2
So each year will decrease by 140km^2
To find till 9th years it will be
4000-(140*9)=2740 km^2
Area after 9 years is 2740 km^2

7 0

3 years ago

A bag contains 17 cards numbered 1 through 17 . A card is randomly chosen from the bag. What is the probability that the card ha

Pachacha [2.7K]

Answer: 8/17

Explanation:
2, 4, 6, 8, 10, 12, 14, 16 are all the possible even numbers from 1 through 17.

6 0

4 years ago

1) simplify [1/2 divided by (-1/2 divided by 1/2)] divided by 2/5

nikklg [1K]

Answer:

After division, the answer we would get is 0.025

5 0

3 years ago

Read 2 more answers

Which equation is a point slope form equation for line AB ? y+1=2/3(x−4) y+1=3/2(x−4) y+1=−2/3(x−4) y+1=−3/2(x−4) A graph with a

Rufina [12.5K]

Answer:

C) y + 1 = -2/3(x - 4)

Step-by-step explanation:

The given line passes through the points A (4, -1) and B (-2, 3)

Let's find the slope now.

Slope (m) = (y2 - y1)/(x2 - x1)

= (3 - (-1)) / (-2 - 4)

= (3 + 1)/-6

= 4/-6

Slope (m) = -2/3

The equation of line y - y1 = m (x - x1)

y - (-1) = -2/3(x - 4)

y + 1 = -2/3(x - 4)

Answer: C) y + 1 = -2/3(x - 4)

Thank you.

5 0

3 years ago

A total of $6000 was invested, part of it at 3% interest and the remainder at 8%. If the total yearly interest amounted to $380,

Nastasia [14]

$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest

Solution:

Given that, total of $6000 was invested

Let "x" be the amount invested at 3 % interest

Then, (6000 - x) is the amount invested at 8 % interest

Given that,

The total yearly interest amounted to $380

Then, we can frame a equation as:

$x \times 3 \% + (6000 - x) \times 8 \% = 380$

Solve the above expression for "x"

$x \times \frac{3}{100} + (6000-x) \times \frac{8}{100} = 380\\\\0.03x + (6000-x) \times 0.08 = 380\\\\0.03x + 480 - 0.08x = 380\\\\-0.05x = -100\\\\\text{Divide both sides by -0.05 }\\\\x = 2000$

Thus, $ 2000 is invested at 3 % interest

(6000 - x) = 6000 - 2000 = 4000

$ 4000 is invested at 8 % interest

4 0

4 years ago