Question

The average time to serve a customer at a fast-food restaurant is 4.35 minutes. The standard deviation of the service time is 2.5 minutes. What is the coefficient of variation of the service time

Answer 1

Answer: 0.5747

Step-by-step explanation:

Given: Average time to serve a customer$(\mu)=4.35$ minutes

standard deviation of the service time $(\sigma)=$ 2.5 minutes

coefficient of variation = $\frac{\sigma}{\mu}$

$=\dfrac{2.5}{4.35}\\\\=\dfrac{250}{435}\\\\=0.5747$

Hence, the required coefficient of variation= 0.5747