<span>Rules for rotating points about the origin
1. The point (a,b) rotated 90° counterclockwise about
the origin
becomes (-b,a).
</span><span>A′ (-1, 3) B′ (-2, 2) C′ (-2, 1) D′ (-1, 1)
</span>A (a,b)-----------------A′ (-b,a)=(-1, 3)----------->A( 3,1)
B (a,b)-----------------B′ (-b,a)=(-2, 2)----------->B( 2,2)
C (a,b)-----------------C′ (-b,a)=(-2, 1)----------->C( 1,2)
D (a,b)-----------------D′ (-b,a)=(-1, 1)----------->D( 1,1)
The limits to the given function are as follows:
1. ∞
2. -∞
3. ∞
4. 1
5. -∞
<h3>What is a limit?</h3>
A limit is given by the <u>value of function f(x) as x tends to a value</u>.
For this problem, at x = 0, we have that to the left the function goes to positive infinity, while to the right it goes to negative infinity, hence:
1. lim f(x) = ∞
x->0-
2. lim f(x) = -∞
x->0+
At x = 2, the function goes to infinity to the left and to the right, hence:
3. lim f(x) = ∞
x->2
To the left of the graph, the function goes to negative infinity, while to the right it goes to 1, hence:
4. lim f(x) = 1
x-> ∞
5. lim f(x) = -∞
x-> -∞
More can be learned about limits of functions at brainly.com/question/26270080
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Answer:
Common Difference: 
The ninth term: -1
Step-by-step explanation:
The sequence can be written like this,
3, 2.5, 2, 1.5, 1, ....
Here the common difference is clearly -0.5 or , and we can conclude that 
number is 
. So the 9th term is,
For
y=a(x-h)^2+k
vertex is (h,k)
given
y=1(x-2)^2-5
the vertex is (2,-5)
tha'ts quadrant 4
andswer is 2nd one
The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.
