2cos theta = 1 -> cos theta = 1/2
Then theta = pi/3 + 2npi or -pi/3 + 2npi, where n is random interger
And the domain is restricted in [0,2pi]
So answer will be pi/3 or 5pi/3
The answer is D as it can be rewritten as -((y^2)/5)-(8/5)=x. Solving for the x-intercepts you get -((y^2)/5)-(8/5) = 0 as you want to find the y values when x is zero. Solving for y you get: (y^2)/5)+(8/5) = 0 => (y^2)/5)=-(8/5) => y^2=-8 => y = plus or minus sqrt(-8). The first problem is that you have 2 x intercepts which already makes it not a function and second sqrt(-8) is an imaginary number making the solution not a real number.
Answer:
(3,2)
Step-by-step explanation:
take negative from inside bracket as x and contant outside as y, and done
<span> 9.187 to the nearest tenth is 9.2
The 1 in 9.187 is in the tenths place and since the number after it is over 5, you round up. </span>
