Answer:

Step-by-step explanation:

I hope I helped you^_^
You just need to divide 13 and 2 and get 6.5.
Answer:
The answer is A.
.
Step-by-step explanation:
To find the difference of this problem, start by simplifying the denominator, which will look like
. Next, multiply
by
to create a fraction with a common denominator in order to subtract from
. The problem will now look like
.
Then, simplify the terms in the problem by first multiplying
and
, which will look like
. The next step is to combine the numerators over the common denominator, which will look like
.
Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of
, which will look like
. Then, subtract 14 from -7, which will look like
. The final answer will be
.
Answer:

Step-by-step explanation:
Given

Required
Determine the period
A sine function is represented as:

Where

By comparing:
and 

So:

So, we have:



Hence, the period of the function is 
Hello :
<span>the parabola's equation is : f(x) = a(x+3)²-1
</span><span>the coefficient of the squared expression in the parabola's equation is : a
but ; f(4) = 0
0 = a(4+3)²-1
49a-1=0.....a=1/49
f(x) = 1/49(x-3)²-2</span>