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Ivanshal [37]
3 years ago
15

!! please, help me with this. i dont know what to do!!!

Mathematics
1 answer:
Sholpan [36]3 years ago
8 0
The answer is 22. Divide 32 by 71.
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The sum of 5 consecutive odd numbers is 145.
Anna007 [38]
Let x be the first odd integer. x + 2 the second x + 4 the third x + 6 the fourth x + 8 the fifth. add them up and you get 5x + 20 set 5x + 20 = 145 and solve for x. 5x=145-20 5x=125 x=25 answer=25,27,29,31,33
7 0
4 years ago
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There were two lions .Each lion had two cubs. How many lions were there in all?
german
Two lions plus two Cubs per each line equals six lions.
4 0
3 years ago
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2/3 - 4/3 whats the answer how to solve
Arisa [49]

Answer:

-2/3

Step-by-step explanation:

3 0
3 years ago
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A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
4 years ago
How do you solve this
mars1129 [50]

Answer:

The inquality is always false i think..

Step-by-step explanation:

8 0
4 years ago
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