the second one
Step-by-step explanation:
because if you see good the second one have the dimensional in the same way
Answer: Y= -5x+2
First we need to find slope
M= y2-y1/x2-x1
M= -3-2/1-0
M= -5/1
M= -5
Now using slope intercept form we can solve this equation
Y-y1=m(x-x1)
Y-2=-5(x-0)
Y-2=-5x+0
Y= -5x+2
hope this helps!!
Please tell me if I am incorrect, I enjoy learning from my mistakes:)
Answer:
The answer to your question is h = 125.85 ft = 126 ft
Step-by-step explanation:
Process
1.- Determine two equations to solve the problem
(1)
(2)
from (1) h = xtan14
substitute in (2) tan 47 = 
solve for x tan47(x - 386) = xtan14
1.07x - 413.9 = 0.25x
1.07x - 0.25x = 413.9
0.82x = 413.9
x = 413.9/0.82
x = 504.76 ft
2.- Calculate h
h = 504.76 tan 14
h = 125.85 ft = 126 ft
Answer:

Step-by-step explanation:
<u>Mathematical Modeling</u>
To model a real-life situation, a mathematical model can be constructed in such a way it accurately represents the variables measured in the system.
This problem requires to build a model for the yearly cost of a small and successful business.
The first data is the fixed monthly cost or the money the owner must pay regardless of the number of employees he hires. This cost includes shipping supplies and products for $2,000. To operate for a full year, the fixed cost is 12*$2,000=$24,000.
The other component of the cost function is the variable cost of x employees. Given each employee costs $1,600 each month, having x employees cost 1,600x each month. For a full year, the variable cost will be
12*1,600x=19,200x.
We finally form the total cost function:

Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640