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vampirchik [111]
3 years ago
8

The Warren family was saving up for their summer vacation. Mrs. Warren had $486.88 in their savings account for the trip. Mr. Wa

rren received a bonus at work for $320.00 that he is saving for the trip. If the trip will cost the Warren's a total of $1560.98, how much more money do they need for their vacation? A. $754.10 B. $806.88 C. $1,366.10 D. $2,367.86
Mathematics
1 answer:
borishaifa [10]3 years ago
6 0

Answer: A. $754.10

Step-by-step explanation:

$320.00 + $486.88 = $806.88

$1,560.98 - $806.88 = $754.10

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Which two-dimensional net does not represent a three-dimensional rectangular prism?
spin [16.1K]

the second one

Step-by-step explanation:

because if you see good the second one have the dimensional in the same way

7 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the line between the two points.
DENIUS [597]
Answer: Y= -5x+2
First we need to find slope
M= y2-y1/x2-x1
M= -3-2/1-0
M= -5/1
M= -5
Now using slope intercept form we can solve this equation
Y-y1=m(x-x1)
Y-2=-5(x-0)
Y-2=-5x+0
Y= -5x+2
hope this helps!!
Please tell me if I am incorrect, I enjoy learning from my mistakes:)
5 0
2 years ago
ASAP: I need as soon as possible with this question I have taken a picture of. If you could tell me how to do it and the answer,
VladimirAG [237]

Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

    tan 14 = \frac{h}{x}                     (1)

    tan 47 = \frac{h}{x - 386}           (2)

    from (1)                           h = xtan14

    substitute in (2)             tan 47 = \frac{xtan14}{x - 386}

    solve for x                     tan47(x - 386) = xtan14

                                          1.07x - 413.9 = 0.25x

                                          1.07x - 0.25x = 413.9

                                           0.82x = 413.9

                                           x = 413.9/0.82

                                           x = 504.76 ft

2.- Calculate h

                                          h = 504.76 tan 14

                                          h = 125.85 ft = 126 ft

4 0
3 years ago
Owning a small and successful business isn't easy! There is a monthly cost of shipping supplies and
andriy [413]

Answer:

C(x)=24,000+19,200x

Step-by-step explanation:

<u>Mathematical Modeling</u>

To model a real-life situation, a mathematical model can be constructed in such a way it accurately represents the variables measured in the system.

This problem requires to build a model for the yearly cost of a small and successful business.

The first data is the fixed monthly cost or the money the owner must pay regardless of the number of employees he hires. This cost includes shipping supplies and products for $2,000. To operate for a full year, the fixed cost is 12*$2,000=$24,000.

The other component of the cost function is the variable cost of x employees. Given each employee costs $1,600 each month, having x employees cost 1,600x each month. For a full year, the variable cost will be

12*1,600x=19,200x.

We finally form the total cost function:

\boxed{C(x)=24,000+19,200x}

7 0
3 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
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