Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
2/5 were sold in the morning. This is equal to 40% of the total. That leaves 60% leftover.
3/4 were sold in the afternoon. This is equal to 75% of the 60% leftover or 45% of the total (.6x.75).
The difference between the two sales is 24 cartons or 5% (45%-40%). If 5% is equal to 24 then you can cross multiply to see what is the equivalent number of cartons out of 100%.
5/100 = 24/x
5x = 24(100)
5x = 2400
x = 480
ANSWER: 480 cartons
Answer:
She uses 200 milliliters of solution B
Step-by-step explanation:
Notice that there are two unknowns in this problem: 1) the amount of solution A that is being used, and 2) the amount of solution B being used. We can name such unknowns with letters to facilitate our work:
Amount of solution A to be used = A
Amount of solution B to be used = B
So, since we need to find two unknowns, we need to create a system of two equations to solve them.
Our first equation can be obtained from the sentence: "She uses twice as much Solution A as Solution B," which written in mathematical form is:
A = 2 B
The second equation we can build from the information of the amount of alcohol in each solution that combined will add up to 104 milliliters of alcohol in the mixture. Knowing the percent of alcohol in each solution, we can write an equation for the amount of alcohol:
0.19 A + 0.14 B = 104
Now we can use our first equation to substitute A in terms of B in the second equation:
0.19 (2 B) + 0.14 B = 104
0.38 B + 0.14 B = 104
0.52 B = 104
B = 104 / 0.52
B = 200 milliliters
3x + 5y = 10 Subtract 3x from both sides.
5y = -3x + 10 Divide both sides by 5.
y = -3/5x + 2
