Answer:
Probability that a randomly selected broiler weighs more than 1454 g is 0.3372 or 34% (approx.)
Step-by-step explanation:
Given:
Weights of Broilers are normally distributed.
Mean = 1387 g
Standard Deviation = 161 g
To find: Probability that a randomly selected broiler weighs more than 1454 g.
we have ,


X = 1454
We use z-score to find this probability.
we know that


P( z = 0.42 ) = 0.6628 (from z-score table)
Thus, P( X ≥ 1454 ) = P( z ≥ 0.42 ) = 1 - 0.6628 = 0.3372
Therefore, Probability that a randomly selected broiler weighs more than 1454 g is 0.3372 or 34% (approx.)