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Alexxandr [17]
3 years ago
6

I will mark you brainliest if you help me im not lying

Mathematics
2 answers:
aksik [14]3 years ago
5 0

Answer:

60 miles

I hope this helps.

trasher [3.6K]3 years ago
3 0

Answer:

Jim ran 60 miles.

Step-by-step explanation:

So Toby ran 5 miles.

Kate ran 4 times as much as Toby

5x4 = 20

Jim ran 3 times as much as Kate.

3x20 = 60

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A large rock (mass = 4.0 kg) moving at a velocity of 2.0 m/s has a momentum of _______ kg*m/s
Elodia [21]

Step-by-step explanation:

❁ \underline{ \underline{ \text{Given} }}:

  • Mass of a large rock ( m ) = 4.0 kg
  • Velocity ( v ) = 2.0 m/s

❁ \underline{ \underline{ \text{ \: To \: find}}}:

  • Momentum ( p )

✑ \underline{ \underline{ \text{Solution}}} :

\boxed{ \underline{ \sf{Momentum \:  =  \: mass \:  \times  \: velocity}}}

plug the known values :

⟹ \sf{Momentum = 4.0 \: kg \:  \times  \: 2.0 \:m/s }

⟹ \sf{Momentum = 8 \: kg \: m/s}

\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer :   \bold{ \underline{8} }\: kg*m/s}}}}

⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆

✑ \underline{ \underline{ \text{Learn \: more about \: momentum}}}:

Imagine that a car and a truck both have the same speed on the road. Which one can stop easily ? Of course , it is hard to stop the truck relative to the car. The reason is that the car and the truck have the same speed bit different masses. Thus , we can say that to stop a heavier body is harder than to stop a lighter one even both of them have the same speed.

If two tennis balls are hit towards you in different velocities , it is not equally easier to stop them. The ball in more velocity is difficult to stop relatively. Thus , we can say that to stop a body in more velocity is harder than to stop a body with less velocity , eventhough they have the same speed.

The physical quantity that describes the quantity of motion of a body is called momentum. The momentum of a moving body or linear momentum is defined as the product of mass & velocity of a moving body.

Mathematically ,

Momentum = mass × velocity

i.e p = m × v

The SI unit of momentum is kg • m/s. Since velocity is a vector quantity and multiplied with mass ( scalar quantity) , momentum becomes a vector quantity. Direction of momentum is the same as velocity.

Hope I helped ! ♡

Have a wonderful day / night ツ

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7 0
3 years ago
What is( -10a^5-2a^5+14a^5)(12a^5-6a-10a^3)<br><br> using distributive and the area model.
Delvig [45]
(-10a^5-2a^5+14a^5)(12a^5-6a-10a^3) \\ = 2a^5 (12a^5-6a-10a^3) \\ = 24a^{10} - 12a^6 - 20a^8
8 0
3 years ago
The Product of a number m and 23​
damaskus [11]

Answer:

23m

Step-by-step explanation:

The product of a number m and the numeral 23 is 23m.

6 0
3 years ago
SOLVE: High school precal
allochka39001 [22]
Tbh idk I just need help passing a class
3 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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