4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left
First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one
70 this is your answer i hope
Answer:
what
Step-by-step explanation:
Answer:
<em>Answer: D</em>
Step-by-step explanation:
<u>Arithmetic Sequences
</u>
The arithmetic sequences are those where any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.
The equation to calculate the nth term of an arithmetic sequence is:
Where
an = nth term
a1 = first term
r = common difference
n = number of the term
We are given the arithmetic sequence:
10, 12, 14, 16, ...
Where a1=10 and
r = 12 - 10 = 2
Thus the general term is:
Operating:
Answer: D
Answer:
a)148.47
b)148.34
Step-by-step explanation:
Let π(x) be the prime-counting function that gives the number of primes less than or equal to x, for any real number x. For example, π(7) = 4 because there are four prime numbers (2, 3, 5, 7) less than or equal to 7.
We can see that π(7)=π(10) because there are four prime numbers (2,3,5,7) less than or equal to 10.
A good aproximation for π(x) is x / log x, where log x is the natural logarithm of x.
a)The number of primes between 1 and 1030.
1030/log(1030)=148.47
b) The number of primes between 1 and 1029.
1029/log(1029)=148.34
Extra: π(1029)=π(1030) because 1030 is not a prime.
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