Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Answer:
a^6
Step-by-step explanation:
a^1 * a^2 * a^3 = 1+2+3(add all power when same variable)
a^6
30,60,90,120
40,80,120
they will both " ash " in 120 seconds (thats 2 minutes)...so they will both ash at
10:42 a.m.
So the total number of students is 50, and you want to find 32/50. and that is equal to 64%
The answer is 24. You subtract 40 - 16.