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Anastaziya [24]
3 years ago
6

Help me solve this !!! Math problem!

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

The probability that she would succeed is 1/2

Step-by-step explanation:

Firstly. we have to calculate the area of the board

That would be the area of the rectangle

This is the product of the base and the height which is 50 cm * 40 cm = 2,000 cm^2

The area of the triangle is the area of the base and the height divided by 2

we have this as;

1/2 * 50 * 40 = 1,000 cm^2

The probability would be the area of the triangle divided by the area of the board

This is because she is aiming at the triangle while having the whole board to work against

This is 1,000 cm^2/2000 cm^2 = 1/2

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You would want to divide 6 by 2, getting x=3.

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klemol [59]
         6x + 3 = -4y + 11
               - 3            - 3
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6x - 6x + 4y = -6x + 8
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6 0
3 years ago
5-<br><br><br> pls help!!!!<br><br><br><br> math<br><br><br> -
Sedbober [7]

Answer:

5,-1

Step-by-step explanation:

  2,3

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6 0
2 years ago
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Please answer this! Im desperate UvU,
Ratling [72]
Part A:

x=5
4x-1 ≤19
4(5)-1 ≤19
20-1 ≤19
19 ≤19

x=5
4x-1<19
4(5)-1<19
19<19

Explanation:
In problem one the greater then symbol has a line under it, this means that the symbol now means greater then or equal to. Since 19 is equal to 19 it is correct. In problem to the greater then symbol has no line under it meaning it only means greater then. Since 19 is not greater then 19 it is false.
So basically the difference is:
≤ = greater then or equal to
< = greater then


Part B:
5x+2=47
-2 -2
5x=45
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x=9

Explanation:
Since when you solve the equation x=9 the value 9 from the set makes the equation.


Hope this helped :)
6 0
3 years ago
Brainliest question Please help me now plz
Novosadov [1.4K]

Answer:

A. Inside the circle

Step-by-step explanation:

K(0, 0), U (6, - 4), V (\sqrt 2,\: 7)

In order to determine whether point V lie inside, outside or on the circle, first we will find the distances between points K & U and then K & V.

KU would be radius of the circle.

  • If KV is smaller than KU, then V will lie inside.
  • If KV is larger than KU, then V will lie outside
  • And If KV = KU, then V will lie ion the circle.

d(KU)  =  \sqrt{ {(6 - 0)}^{2} +  {( - 4 - 0)}^{2}  }  \\  =  \sqrt{ {6}^{2}  +  {( - 4)}^{2} }  \\  =  \sqrt{36 + 16}  \\  \red{ \bold{ d(KU)=  \sqrt{52} }} \\  \\ d(KV)  =  \sqrt{ {( \sqrt{2}  - 0)}^{2} +  {( 7 - 0)}^{2}  }  \\  =  \sqrt{ {( \sqrt{2)} }^{2}  +  {(7)}^{2} }  \\  =  \sqrt{2 + 49}  \\  \purple{ \bold{ d(KV)=  \sqrt{51} }} \\  \\  \because \: d(KU) > d(KV) \\

Hence point V lie inside of the circle.

3 0
3 years ago
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