Pretty sure the answer is k
The first and crucial thing we want to take notice is that the lines DF and EG intersect at point H which creates 4 different triangles in the rhombus. The innermost angles of DGH and EFH are vertical angles and vertical angles are congruent. So if the angles of the triangles are congruent than the triangles themselves are congruent. This is supported by the vertical angles theorem.
Esmeralda I think it's wrong cuz it’s like the question but that's added a parentheses so I think that's wrong
Answer:
x = 30°.
Step-by-step explanation:
The dashes on the three lines indicate that the three lines are of equal lengths. The smaller triangle made out of the three lines (the one with two vertices on the circumference of the circle and one at the center of the circle) is an isosceles triangle. All three of the triangle's interior angles are 60° since it is isosceles.
The line (the one with arrows on its ends) touches the circle at only one point. That line is a tangent to the circle. That line is perpendicular to the segment that connects the center of the circle to the point of tangency. The angle between the two will be 90°.
The largest triangle includes three angles:
- The angle with the center of the circle as its vertice: 60°;
- The right angle due to the tangent to the circle: 90°;
- The angle x°.
What is the value of x?
The three interior angles of a triangle add up to 180°. As a result,
60° + 90° + x° = 180°
x = 180 - 90 - 60 = 30.
Answer:
8 can go into eighteen 2.25 times
