Find the value of variable in the figures below. round answers to the nearest hundredth

Can someone please help me really quickly itis due at midnight tonight.

kicyunya [14]

Answer:

4 or -4 !

Step-by-step explanation:

edit... isolate the variable, so divide 5 on both sides. then take the absolute value of d which is d. therefore d = 4 or -4! it's both positive and negative because absolute value you set it equal to a positive and negative!

8 0

3 years ago

GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!

Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

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The first equation is of the line.
The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

$x + 2y = 6$

$2y = 6 - x$

$y = -0.5x + 2$

Thus it is a decreasing line, which removes options J.

We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

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As for the second equation, the normalized equation is:

$3x^2 + 3y^2 = 12$

$3(x^2 + y^2) = 12$

$x^2 + y^2 = 4$

Thus, a circle centered at the origin and with radius 2.
Now, we have to check if the line $x + 2y - 6 = 0$ , with coefficients $a = 1, b = 2, c = -6$ , intersects the circle, of centre $x = 0, y = 0$
First, we find the following distance:

$d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}$

Considering the coefficients of the line and the center of the circle.

$d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1$

This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0

3 years ago

Find the midpoint of H(13,8) and X(-6,-6)

GrogVix [38]

$coordinates\ of\ midpoint \ M(x,y)\\\\ 
endpoint:\ A(13,8)\\
endpoint:\ B(-6,-6) \\\\ 
M(x,y)=(\frac{x_A+x_B}{2}\ ;\ \frac{y_A+y_B}{2})\\\\
M=(\frac{13-6}{2},\frac{8-6}{2})\\\\
M=(3.5;1)$

5 0

4 years ago

How do I find a parallel equation?

STatiana [176]

Parallel are two equations that have the same slope but different y intercepts.

If the y intercepts are also the same, it is just the same line.

6 0

4 years ago

Solve each system by elimination. Check the solution in both of the original equations.

elena55 [62]

Answer:

After finding the solution of given equations by elimination method

-3x-3y=12

-9x+3y=-24

we get the value of x=1 and y= -5

Step-by-step explanation:

$-3x-3y=12$ is eq A

$-9x+3y= -24$ is eq B

To find out value of x and y we will use elimination method

To find value of x add eq A and eq B

$(-3x-3y)+ (-9x+3y)= 12 + (-24)\\-3x-3y-9x+3y= 12-24\\-12x = -12\\dividing \,\,by -12\,\,on\,\, both\,\,sides\\\frac{-12x}{-12} = \frac{-12}{-12} \\x= 1$

Now to find value of y put x=1 in eq A

$(-3 \times 1 )- 3 y=12\\-3 -3y =12\\\\adding\,\,3\,\,on\,\, both\,\,sides\\-3y=12+3\\\\dividing\,\,-3\,\,on\,\,both\,\,sides\\y= \frac{15}{-3} \\y= -5$