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yan [13]
3 years ago
7

Is quadrilateral ABCD a parallelogram? Explain.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0

Answer:

don't know

Step-by-step explanation:

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A combination lock has numbers 0-49 on it. How many different 3-digit lock
Harman [31]

Answer:

19,600

Step-by-step explanation:

0-49=50 numbers

n=50

r=3

C(n,r)=n!/(r!(n-r)!)

=50!/(47!)(3!)

C(n,r)=C(50,3)

=50!/(3!(50−3)!)

= 19600

3 0
3 years ago
Three squares. The first square is labeled with side length 1 inch on the vertical side and 1 inch on the horizontal side. The s
dlinn [17]

Answer:

The area is the side lengths squared or multiplied by themselves. The three squares have very different areas based on their side lengths. I disagree that a square with 13 inch side length will have area 13. It will have area 13*13=169 square inches.

Step-by-step explanation:

The area of a square is A=s*s.

1st: A = 1*1 = 1 square inches.

2nd: A=1/2*1/2 = 1/4 square inches

3rd: A =2*2 = 4 square inches.

The area of a square with 1 unit side length is still 1. But a square whose side is less than 1 has a very small area and the square whose side length is greater than 1 has a much larger area. The area of a square is the square of its side length or its side length times itself.

Knowing this, a square with side length 13 will not have area 13 but area 169.

8 0
3 years ago
There are two bookcases against a wall. If one takes up 4/7 of the wall and the other takes up 2/8 of the wall, how much of the
Airida [17]
23/28 of the wall is covered by bookcases
3 0
4 years ago
HEEP! I WILL GEV YOU BRANLEST! <br><br> Wats 1+1? I ma so confsed
Allisa [31]

Answer:

2 or wrong answer 55

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
In the right triangle shown, AC = BCAC=BCA, C, equals, B, C and AB = 6AB=6A, B, equals, 6.
alexandr402 [8]

Answer:

|AC|=|BC|=3\sqrt{2}

Step-by-step explanation:

In a right triangle, the hypotenuse is always the longest side. Since AC = BC, AB is the Hypotenuse.

Using Pythagoras theorem

|AB|=6,|AC|=|BC|\\|AB|^2=|AC|^2+|BC|^2\\6^2=2|AC|^2\\36=2|AC|^2\\18=|AC|^2\\|AC|=\sqrt{18}=3\sqrt{2}  \\Therefore,  |AC|=|BC|=3\sqrt{2}

8 0
3 years ago
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