This is false, because the equation is then 12=2, which is incorrect.
Hope this helps!
~ThePirc
__-____-1,58____+_____0_______-__1,58_____+____>x
Locol max: 0
If you don’t mind me asking what is the question I’m confused because I might be able to help but I have no clue what the question is.
Givens
AB + BC = AC
AB = 2(x + 1)
BC = 3x + 1
AC = 4(x + 2)
Substitute and Solve
AB + BC = AC
2(x + 1) + 3x + 1 = 4(x + 2) Remove the brackets on the left
2x + 2 + 3x + 1 = 4(x + 2) Collect the like terms on the left
5x + 3 = 4(x + 2) Remove the brackets on the right.
5x + 3 = 4x + 8 Subtract 4x from both sides.
5x - 4x + 3 = 8
x + 3 = 8 Subtract 3 from both sides
x =8 - 3
x = 5
Answers
AB=2(5 + 1) = 2 * 6 = 12
BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16
AC = 4(5 + 2) = 4*7 = 28
This equation is y = mx + b, where m is the slope.
If y = mx + b is ?// to y = - 3x + 7, that means they have the SAME SLOPE, so
y = - 3x + b. To calculate b, plug in the related value of (2,-4)
- 4 = - 3(2) + b
- 4 = - 6 + b and b = -4 + 6 = +2
Hence the final equation is y = -3x +2
