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Savatey [412]
3 years ago
15

Given that

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0
X=x; a=6
x^2 + x^2 = 6^2 (pythagorean theorem)
2x^2 = 36
x^2 = 36/2 = 18
x = square root of 18
x = 2.62 (to the nearest hundredth)
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For which equation would x = 5 be a solution?
tresset_1 [31]

Answer:

The second option.

3x + 6 = 21.

Step-by-step explanation:

3x + 6 = 21.

If x = 5, plug it in.

3 · 5 + 6 = 21

15 + 6 = 21

Hope this helps,

Davinia.

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borishaifa [10]
The value of 7 is in the hundreds place
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Find the area of the shape shown below.
maw [93]

Answer:

The area is 28.

Step-by-step explanation:

Visualize the rectangle as 2 split squares.

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Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4)\frac{1}{2} . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.

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Question 3 (Multiples and Factors] Three numbers are given below. Use prime factorisation to determine the HCF and LCM 1848 132
Ilia_Sergeevich [38]

Prime factorization involves rewriting numbers as products

The HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

<h3>How to determine the HCF</h3>

The numbers are given as: 1848, 132 and 462

Using prime factorization, the numbers can be rewritten as:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

The HCF is the product of the highest factors

So, the HCF is:

HCF = 2 * 3 * 11

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<h3>How to determine the LCM</h3>

In (a), we have:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

So, the LCM is:

LCM = 2^3 * 3 * 7 * 11

LCM  = 1848

Hence, the HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

Read more about prime factorization at:

brainly.com/question/9523814

4 0
2 years ago
Two trucks leave a warehouse at the same time. one travels due west at an average speed of 49 miles per hour, and the other trav
Gre4nikov [31]

Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.

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4 0
3 years ago
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