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Westkost [7]
3 years ago
15

How can 2/3 + 3/12 be rewritten so they can be added?

Mathematics
2 answers:
babymother [125]3 years ago
7 0

Answer:

11/12

Step-by-step explanation:

To rewrite two fractions to add them, you should first look at the denominators, or the bottom numbers. If they aren't the same, you need to find the least common multiple to make them the same.

3 and 12 are our two denominators for this question.

Since these two numbers are not the same, we need to find a number that both work.

We know that 3 goes into 12 four times, because 3 x 4 = 12.

So we can multiply 2/3 by 4/4 to make the denominator become 12.

This looks like this:

\frac{2}{3} * \frac{4}{4} =\frac{8}{12}

Remember, 4/4 equals 1, so we're not changing 2/3, we're just changing how we write it.

Now that we have 8/12, we can add 8/12 to 3/12.

\frac{8}{12} +\frac{3}{12} =\frac{8+3}{12} =\frac{11}{12}

And continue to simplify until you have your answer, 11/12!

Please mark Brainliest! :)

Drupady [299]3 years ago
6 0

well, you can multiply the values to where they are equivalent, so multiply 2/3 by 4 ( both numbers ) so you get 8/12 and 3/12, so, just in case you want POST added, the answer to 2/3 ( 8/12 ) + 3/12 = is 11/12!

Hope this helps, if not, comment below please!!!

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Answer: The three consecutive odd integers are:  -15, -13, and -11 .
_______________________________________________________
Explanation:
_____________________________________________
  x + (x + 2) + (x + 4) = -39 ;
_____________________________________________
 in which "x" is one of the integers, 
           "(x + 2)" is the next consecutive odd integer;
           "(x + 4)"  is the third consecutive odd integer.
__________________________________________
By solving for "x", we can solve for each of three (3) consecutive odd integers.
________________________________________________________
     x + (x + 2) + (x + 4) = -39  ;
_________________________________________________________
          1x + 1x + 2 + 1x+ 4 = -39 ;
_____________________________________________________  
                   3x + 6 = -39 ;
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               Subtract  "6" from EACH side of the equation:
______________________________________________
                    3x + 6 − 6  =  -39 <span>− 6 ;
____________________________________________________
        to get:   3x = -45 ;
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           Divide EACH side of the equation by "3" ;
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                 3x / 3 = -45 / 3 ;
_____________________________________________________
        to get:   x = -15 ;
______________________________________________________
     x + 2 =  -15 + 2 = -13 ;
_______________________________________________________
     x + 4 =  -15 + 4 =  -11 .
___________________________________________________
Are: -15, -13, and -11 ;  Consecutive odd integers?  YES!
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Does:  -15 + (-13) + (-11)  =? = -39 ??
_____________________________________________________
           -15 </span>− 13 <span>− 11 = ? 39 ??  YES!
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Answer: The three consecutive odd integers are:  -15, -13, and -11.
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