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3 years ago

Hello, I would really like some help on this!! Please leave an explanation of how you got your answer! Thank You!

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

6 0

1a) To find the total area, you must find the area of the triangular part that is missing, then subtract this from the area of the rectangle. For the triangle’s area, you need to know the width (2m) and length (2m). For the rectangle’s area you need to know the width (3m) and length (4m).
1b) the total area is 10m^2 (10 meters squared). This is found by subtracting the triangle (.5x2x2=2) from the rectangle (3x4=12).

noname [10]3 years ago

4 0

I don’t know how to answer this question sorry. I’m just answering so the other person can get brainliest.

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Suppose a shipment of 160 electronic components contains 3 defective components. to determine whether the shipment should be ac

Olenka [21]

0.00067% chance it will be rejected.
The probability of each event occurring multiplied together will give us the total probability of one item being defective found in the 3.
1st
3/160
2nd
3/159
3rd
3/158
$\frac{3}{160} * \frac{3}{159} * \frac{3}{158} = \frac{27}{4019520} =0.0000067$

8 0

3 years ago

I need help with the proofs !

lozanna [386]

Answer:

All you have to do is show that both are the same distance from the lines

Step-by-step explanation:

4 0

4 years ago

Can I please get some help on this...I have tried to many times...

Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

$\sqrt{x-2} =0$

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0

4 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago

HELPP!! ANYONE PLEASE

Grace [21]

Answer:

-4/5 + (-7/5) = -1 1/5

Step-by-step explanation:

I got this answer because when you look at where the first arrow is pointing you take that number and add it the the number of jumps you take to get to the end of the second arrow.

7 0

3 years ago