The arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.
To calculate the arrival time in london of a train that leaves Leicester to london at 11:50 A.M, use use the formula below.
Formula:
- Ta = [(d/s)+11:50]....... Equation 1
Where:
- Ta = Arrival time
- d = distance from Leicester to London
- s = Speed
From the question,
Given:
Substitute these values into equation 1
- Ta = [(100/80)+11:50]
- Ta = 1.25h+11:50
- Ta = 1 hours 15 minutes +11:50
- Ta = 13:05 pm
Hence, the arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.
Learn more about time here: brainly.com/question/4931057
Step-by-step explanation:
y=12when x=5
y=5+7
when x=3
y=3+7=10
Answer:
Similar, SSS similarity, ΔLRS
Step-by-step explanation:
First, compare the ratios of the shortest sides:
LN / LS = 112 / 24 = 4⅔
And the longest sides:
LM / LR = 168 / 36 = 4⅔
And the middle:
MN / RS = 154 / 33 = 4⅔
The triangles' sides are proportional. Therefore, by SSS similarity, the triangles are similar.
It means that you have to find the solution of the systems of equations.
Answer:
In the next 31 years
Step-by-step explanation:
In this question, we are tasked with calculating the number of years it will take for a school’s population to reach a certain amount of it is increasing at a certain rate.
We can use a mathematical exponential approach to solve this.
Let’s say;
P = I( 1 + r)^t
where P is the projected population at 926
I is the initial population at 502
r is the percentage change or rate at 2% which is same as 2/100 = 0.02
and t is time
Plugging these values, we have
926 = 502(1 + 0.02)^t
Divide through by 502
1.845 = 1.02^t
take the logarithm of both sides
log 1.845 = tlog 1.02
t = log 1.845/log 1.02
t = 30.9 = 31 years
