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Lady_Fox [76]
3 years ago
7

A forest covers 57,000 acres. A survey finds that ​0.4% of the forest is​ old-growth trees. How many acres of​ old-growth trees

are​ there?
Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

228

Step-by-step explanation:

0.4% = 0.004

0.004 x 57000 = 228

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What is the difference between 6 2/4 and 1/6????? PLEASE HELP ME
VashaNatasha [74]

Answer:

6 2/4 is a mixed fraction and 1/6 is not.

Step-by-step explanation:

8 0
3 years ago
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Is v = -1 / 3 a solution of 9v-2= 3v?
Gre4nikov [31]

Answer:

No, -1/3 is not a solution

Step-by-step explanation:

See if it is a solution by plugging in -1/3 as v and seeing if the equation is correct:

9v - 2 = 3v

9(-1/3) - 2 = 3(-1/3)

-3 - 2 = -1

-5 = -1

-5 \neq -1

So, since the equation is incorrect, -1/3 is not a solution.

4 0
3 years ago
Draw pictures to show the number 326
Dovator [93]
3 hundreds 2 tens 6 ones
6 0
3 years ago
Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
4 years ago
n a study of the accuracy of fast food​ drive-through orders, Restaurant A had 314 accurate orders and 61 that were not accurate
Varvara68 [4.7K]

Answer:

a. 0.1576<p<0.2310

b. The two restaurants likely have similar order rates which are inaccurate.

Step-by-step explanation:

a. We first calculate the proportion, \hat p:

\hat p=\frac{61}{314}\\\\=0.1943

-We use the z-value alongside the proportion to calculate the margin of error:

MOE=z\sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\=1.645\times \sqrt{\frac{0.1943(1-0.1943)}{314}}\\\\=0.0367

The confidence interval at 90% is then calculated as:

CI=\hat p\pm MOE\\\\=0.1943\pm 0.0367\\\\=[0.1576,0.2310]

Hence, the confidence interval at 90% is [0.1576,0.2310]

b. From a above, the calculated confidence interval is 0.1576<p<0.2310

-We compare the calculated CI to the stated CI of 0.147<p<0.206

-The two confidence intervals overlap each other and have the same value for 0.1576<p<0.206

-Hence, we conclude that the two restaurants likely have similar order rates which are inaccurate.

3 0
3 years ago
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