The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
![5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}](https://tex.z-dn.net/?f=5%5Cleft%28x%2B27%5Cright%29%5Cge%20%5C%3A6%5Cleft%28x%2B26%5Cright%29%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5C%3A-21%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-21%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:
- <em>greater than or equal </em>is written as:
- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer:
To break even it must be molded 1280 handles weekly.
The profit if 1500 handles are produced and sold is $440
Step-by-step explanation:
To break even, the amount of total cost must be the same as the amount of revenues.
Total Cost is Fixed cost plus unitary variable cost multiplied by the produce quantity.
Total cost= FC + vc*Q
Where
FC=Fixed cost
vc=unitary variable cos
Q=produce quantity
Revenue= Price * Q
Break even FC + vc*Q=Price * Q
Isolating Q
FC=(Price * Q)-(vc*Q)
FC=(Price-vc) * Q
Q= FC/(Price-vc)
Q= $2560/($3.00-$1.00)=1280
If we sold 1500 handles
Profit = Revenue- Total cost =(Price * Q)-(FC + vc*Q)
P=$3.00 *1500-$2560 - $1.00*1500=
P=$4500-$2560-$1500=440
20y+30x=1000 divide 20 on each side to st the y alone.
y+30x=50 next put it in slope intercept form
y=30x+50 I don't know if this was te answer you were looking for but I hope it is
Answer:
1/13, 12/13
Step-by-step explanation:
There are 4 aces in a 52 card deck so P(Ace) = 4 / 52 = 1 / 13.
There are 52 - 4 = 48 cards that are not aces out of the whole 52 cards in the deck so P(not Ace) = 48 / 52 = 12 / 13.
