There will be three students left out
The force of friction is given in the scenario:
Force = 500 Newton
and the mass of the runner is 60 kg
To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:

Where 'F' represents the force, 'm' represents the mass, and 'a' represents the acceleration.
Plugging the value of variables we get:

Solving for 'a' (acceleration) we get:
Newton/kilogram or meters/ second squared
So the acceleration of the runner is 8.33 meters/ second squared.
Take a look at the picture and note that the same tick marks represent that they are congruent parts.
A. UV is parallel to JL. Yes, this is correct. They are parallel because they don't intersect at any point.
B. UW = 12KL. This is incorrect. The truth is, UW = (1/2)(KL). If this is a typo error and there should've been a '/' in between 1 and 2, then this is acceptable.
C. UW = VW. As you can see, UKVW is a rectangle. They have two pairs of congruent sides. And UW≠VW, so this is incorrect.
D. UV = UK. The diagonal of a rectangle is never equal with one of its sides. So, this is incorrect.
E. JK = 2VW. Since VW=UK and we can see that twice the length of UK is equal to JK, then this is correct.
'is' in mathematics means equal
'of' in mathematics means multiplication
<span>32% can also be written as 32/100
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