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kakasveta [241]
3 years ago
11

A. 20 b. 5 c. 40 d. 45

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
I think it could be B

By divide but iam not sure sorry if it wronge
Rina8888 [55]3 years ago
6 0

Answer:

C, 40

Step-by-step explanation:

You can set up the equation as 20+4x=180

180 is the total angle of the line

4x=160 and divide each side by 4

x=40

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4(2g-3) = 5(g-2) how do you solve for g
raketka [301]

4(2g-3) = 5(g-2)

8g-12 = 5g-10

8g-5g = 12-10

3g = 2

g = 2/3

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3 years ago
5 ( 3x - 2) = 4 ( 2x + 1)
wariber [46]

Answer:

15x-2=8x+1

13x=9x

i think that's correct im not sure but i hope to help u :)

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3 years ago
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AWNSER ASAP!!!!!!! whats the median for 17,25,23,200,14
Ksenya-84 [330]

Answer:23

Step-by-step explanation:

6 0
3 years ago
Kaitaia has one more than 5 times the number or wristbands that shelly has. Rea has three more than twice the number that shelly
saul85 [17]

Answer: The required expression is 3x+4.

Step-by-step explanation:

Since we have given that

Let the number of wristbands that Shelly has be 'x'

Let the number of wristbands that Kaitaia has be 5x+1

Let the number of wristbands that Rea has be three more than twice the number that shelly has be

'2x+3'

According to question, the expression that shows the number of wristbands more Katia has than Rea is given by

5x+1-(2x-3)\\\\=5x+1-2x+3\\\\=3x+4

Hence, the required expression is 3x+4.

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3 years ago
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PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0
2 years ago
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