Answer:
No. See explanation below.
Step-by-step explanation:
No.
Since 60 × $300 = $18,000, he would be exactly at budget if he needed 60 uniforms and if each uniform cost $300, but he needs more than 60 uniforms, and each uniform costs more than $315, so the total cost is definitely more than $18,000.
Answer:
![A=900(1+\frac{0.06}{2})^{2(t)}](https://tex.z-dn.net/?f=A%3D900%281%2B%5Cfrac%7B0.06%7D%7B2%7D%29%5E%7B2%28t%29%7D)
Step-by-step explanation:
Lets use the compound interest formula provided to solve this:
![A=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
<em>P = initial balance</em>
<em>r = interest rate (decimal)</em>
<em>n = number of times compounded annually</em>
<em>t = time</em>
First, change 6% into a decimal:
6% ->
-> 0.06
Since the interest is compounded semi-annually, we will use 2 for n. Lets plug in the values now and your equation will be:
![A=900(1+\frac{0.06}{2})^{2(t)}](https://tex.z-dn.net/?f=A%3D900%281%2B%5Cfrac%7B0.06%7D%7B2%7D%29%5E%7B2%28t%29%7D)
Answer:
need point my bad
Step-by-step explanation:
What would be equal would be 6.60, because 100/5 is 20. So 3 times 20 is 60. Plus the six so 6+0.6 is 6.60.