Wrong,
You added when you were supposed to divide.
24/30 = 0.8
B² - 4ac
= 8² - 4*(-2)*(-9)
= 64 - 72
= -8
Answer:
Step-by-step explanation:
You have to decompose the figure. Cut it into different sections like squares, triangles, and rectangles so you can find the area. Once you have decomposed it, multiply the sides of each section to find the separate area of each square, triangle, rectangle, etc then add up those areas.
Let's call the aces
for hearts, diamonds, clubs and spades. So,
are red and [ted] c, s[/tex] are black.
Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:
If we want a player to draw two card of the same colour, the following couples are good:

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.
Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.
7/9(.8) is greater. 7 divided by 9 equals .77 rounded to .8 which is greater than 7/10(.7)