The answer is 5, C = 5 units.
Answer:
<h2>x = 0, y = 5, z = 3</h2>
Step-by-step explanation:



Answer: x=7
Step-by-step explanation:
Since AB is a bisector, it cuts the angle in half, and since we know that the angle is a right angle, we know it’s 90 degrees, so knowing that you use the equation 7x-4= 45 (since 45 is half of 90), add 4 to both sides so you have 7x=49, the divide 49 by 7 and you get 7, so x= 7
Answer:
y = -
x + 9
Step-by-step explanation:
0.5x + 0.6y = 5.4
0.6y = -0.5x + 5.4
Multiply 10 on all sides.
6y = -5x + 54
Divide 6 on all sides.
y = -
x + 9