<h3>
Answer: B. 4 units to the right, 5 units down</h3>
The vector notation <4, -5> is the same as writing 
which in my opinion is more descriptive in saying "4 units to the right, 5 units down"
We shift 4 units to the right because of the x+4. Whatever x is, add 4 to it getting x+4. So for instance x = 10 leads to x+4 = 10+4 = 14.
The y-5 is why we shift 5 units down. Eg: y = 37 leads to y-5 = 37-5 = 32.
Add <span><span>4<span>a2</span></span><span>4<span>a2</span></span></span>
and <span><span>4<span>a2</span></span><span>4<span>a2</span></span></span>
to get <span><span>8<span>a2</span></span><span>8<span>a2</span></span></span>
.<span><span><span><span>8<span>a2</span></span>+<span>2a</span></span><span>−5</span></span><span><span><span>8<span>a2</span></span>+<span>2a</span></span><span>-<span>5</span></span></span></span>
If n is the first integer, then n+2 is the second one. The equation for the sum can be written as
n + (n+2) = 24 . . . . . . this equation can be used to solve the problem
2n = 22 . . . . . . . . . . . simplify, subtract 2
n = 11
The integers are 11 and 13.
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I like to solve problems like this by looking at the average of the integers. Here, it is 24/2 = 12. The consecutive odd integers whose average is 12 are 11 and 13.
Answer:
The difference is : 10 - y
Step-by-step explanation:
Let we donate the required difference by 'd'
Now, we need to find difference(d) in such a way that it is y units less than 10. So, Using concept of algebraic expressions :
A number which is less than another can be found by subtracting first number from the second number :
So, the required difference is given by : d = 10 - y
Step-by-step explanation:
Hey there!
The equation of a line which passes through the point (1,1) is <em>(y-1) = m1 (x-1)...............(i)</em> {using one point formula}
Also, another equation which is perpendicular to the line is <em>y = 1/5 x + 4/5..........(ii)</em>
Comparing equation (ii) with y= mx+c, we get;
Slope (m2) = 1/5.
Now, As per the condition of perpendicular lines,
m1*m2 = -1
or, m1 * 1/2 = -1
or, m1= -2
Therefore, m1 = -2.
Keeping the value of m1 in equation (i) we get;
y-1 = -2(x-1)
y-1 = -2x+1
or, y+2x-2= 0
Therefore, the required equation is 2x+y-2= 0.
Hope it helps!
