Answer:
it's between BCF/DCA and BCF/BCA
Answer:Triangular Pyramid Solved Examples Example 1: Find the surface area of a triangular pyramid with the base area is 28cm.sq., the perimeter is 20cm, slant length is 5cm. Solution: Surface area = [Base area] + ½ × Perimeter × [Slant length] = 28 + ½ × 20 × 5 = 28 + 50 = 78 cm.sq.
Step-by-step explanation:
A) -27 + (-32) = -56
-56 + 14 = -45
B) -45 ÷ 5 = -9
-9 × 2 = -18
Well if you want to find work x= it well be x=3y/5