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Sonbull [250]
3 years ago
13

Apond contains 100 fish, ofwhich 30 are carp. If 20 fish are caught, what are the mean and variance of the number of carp among

the 20? What assumptions are you making?
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0

Total fish = 100

Carp = 30

Number of fish caught = 20

The random variable X follows hyper-geometric distribution.

Mean = 30 *20 / 100 = 600/100 = 6

Variance = 30*20/100 * ((20-1)*(30-1)/100-1 + 1-30*20/100)

Variance = 600/100 * 56/99

Variance = 112/33

Assumptions: Is that X follows hyper-geometric distribution with the given information.

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Which statements accurately describe the function f(x) = 3(16)^3/4? Check all that apply.
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Answers:

These are the statements that apply:

The initial value is 3.

The range is y >0.

The simplified base is 8.

Explanation:

1) Given expression:

f(x)=3(16)^{\frac{3}{4} x

2) Check every statement:

a) The initial value is 3?

initial value ⇒ x = 0 ⇒

f(0)=3(16)^{0}=3(1)=3

∴ The statement is right.

b) The initial value is 48?

Not, as it was already proved that it is 3.

c) The domain is x > 0?

No, because the domain of the exponential functions is all the Real numbers.

d) The range is y > 0?

That is correct, the exponential function is continuous, and monotonon increasing.

The limit when x → - ∞ is zero, but y never reaches zero, and the limit when x → ∞ is + ∞, meaning that the range is y > 0.

e) The simplified base is 12?

This is how you simplify the base:

3(16)^{\frac{3}{4} x}=3{{(16}^{(3/4)})}^x=3(16^{3/4}})^{x}=3((2^4)^{3/4})^x=3(2^3)^x=3(8)^x

Which shows that the simplified base is 8 (not 12).

f) The simplified base is 8?

Yes; this was just proved.

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