Complete the square to solve 3x2 + 12x = 9.

C.) Apple offers a buyback program for iPhones after they are 5 years old. They

max2010maxim [7]

Answer: It would not be profitable to sell it back for 100$.

Step-by-step explanation:

It would not be profitable because you might have payed 300-1000$ (Depending what phone you buy) for your phone. It would only be profitable for the older generation of the phones like iPhone 5 and iPhone 6.

4 0

3 years ago

Jose ran 7 out of 10 days. What percent of the days did she run?

Otrada [13]

70% lololol hope this helps

8 0

3 years ago

Read 2 more answers

Identify the slope and y intercept (m= and b= ) y=-4xt6;

erastovalidia [21]

Answer:

y=b slope= 4/1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I really need help. answer asap and both questions plz. thank you for you help!!

lidiya [134]

Hello from MrBillDoesMath!

Answer: x = 4, slope intercept form is y = 2x + 11

Discussion:

A vertical line goes straight up and down. The only thing "fixed" about it is its x value. Hence a vertical line has an equation like "x = ?". As your line passes through (4, -3), with x value 4. its equation is x = 4.

The slope intercept form of a line is " y = mx + b" where m is the slope of the line and b is its y intercept. We are told the desired line is parallel to y = 2x -1 which means both lines have the same slope (which is 2, boldfaced, above). So, we know the slope intercept form is

y = 2x + b

but we are also told the line passes through (-3,5). Substituting these values in the above equation gives

y = 2x + b

5 = 2 (-3) + b

5 = -6 + b

b = 5 + 6 = 11

The final slope intercept form is y = 2x + 11

Regards, MrB

7 0

3 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0

3 years ago