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nignag [31]
3 years ago
14

Consider the following two circles. Circle P with center (-1, 2) and radius 3 and circle Q with center (3, 4) radius 5. What seq

uence of transformations will carry circle P onto circle Q? Select all that apply.
A. Dilation centered at Q, followed by reflection across the y-axis
B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5
C. Translation (x,y) -> (x+4, y+2), followed by dilation centered at Q
D. Dilation (x+y) -> (3/5x, 3/5y), followed by dilation centered at P
E. Reflection over x-axis followed by rotation of 270 degrees
Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

<h2>B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5</h2>

Step-by-step explanation:

<h3>Circle P.</h3>

Centerat (-1, 2).

Radius of 3.

<h3>Circle Q.</h3>

Center at (3, 4).

Radius of 5.

To carry one circle onto the other, their centers and radius must be the same.

So, circle P must be shifted from (-1, 2) to (3, 4), that means the translation is 4 units to the right side and two units upside, this is the first transformation.

The second transformation must be about stretching the circle P, from a radius of 3 to a radius of 5.

Therefore, the right answer is B.

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4 years ago
Read 2 more answers
What is the numerical coefficient of the a^8*b^2 term in the expansion of ((1/3)a^2 - 3b)^6 ?
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In the binomial development, the main problem is calculation of binomial coefficients.

If we want to get term a∧8*b∧2 we see that this is the third member in binomial development (n 2) a∧n-2*b∧2

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(6 2) * ((1/3)a∧2)∧(6-2) * (-3b)2 = (6*5)/2 * ((1/3)a∧2)∧4 *9b∧2= 15*(1/81)*9 *(a∧8b∧2) =

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We finally get numerical coefficient 135

Good luck!!!


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