18. What's the product of 3 2/3 and 14 2/5 ? A. 42 4/5 B. 54 C. 52 4/15 D. 52 4/5

Mathematics

1 answer:

Nookie1986 [14]2 years ago

4 0

Answer:A

Step-by-step explanation:

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Use either Gaussian elimination or Gauss-Jordan elimination to solve the given system or show that no solution exists. (If there

True [87]

Answer:

x1 = t, x2 = -t and x3 = 0

Step-by-step explanation:

Given the system of equation

x1 + x2 + x3 = 0 .... 1

x1 + x2 + 9x3 = 0 .... 2

Subtract both equation

x3 - 9x3 = 0

-8x3 = 0

x3 = 0

Substitute x3 = 0 into equation 1

x1 + x2 + 0 = 0

x1+x2 = 0

x1 = -x2

Let t = x1

t = -x2

x2 = -t

Hence x1 = t, x2 = -t and x3 = 0

5 0

2 years ago

A parabola can be drawn given a focus of

Volgvan

Answer:

$y=-\frac{1}{4}(x-2)^{2}+9$

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at $(2,8)$ .

Directrix of the parabola is $y=10$ .

Let $(x,y)$ be any point on the parabola. Then, from the definition of a parabola,

Distance of $(x,y)$ from focus = Distance of $(x,y)$ from directrix.

Therefore,

$\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|$

Squaring both sides, we get

$(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9$