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zhenek [66]
1 year ago
9

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

true proportion is 0.03. If 476 are sampled, what is the probability that the sample proportion will be less than 0.04
Mathematics
1 answer:
kolbaska11 [484]1 year ago
5 0

The probability that the sample proportion will be less than 0.04 is <u>0.8995</u> or <u>89.95%</u>.

The true proportion (p) is given to be 0.03.

Therefore, Mean (μ) = p = 0.03.

The standard error of sampling distribution can be calculated using the formula σ = √[{p(1 - p)}/n], where n, is the sample size, that is, n = 476.

Therefore, σ = √[{0.03(1 - 0. 03)}/476] = 0.00782.

Since, np = 14.28 and n(1 - p) = 461.72 are both greater than 5, we assume the sample is normally distributed.

Since, we are asked to find the probability that the sample proportion is <u>less than</u> 0.04, we using our calculator, enter as following:

Normalcdf(-100000000,0.04,0.03,0.00782), which gives us the value 0.8995 or 89.95%.

Thus, the probability that the sample proportion will be less than 0.04 is <u>0.8995</u> or 89.95%.

Learn more about probability of sampling distributions at

brainly.com/question/15520013

#SPJ4

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A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.
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Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that N = 8 + 10 = 18

We want 3 boys, so k = 8

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that n = 8

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

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