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Harman [31]
3 years ago
6

I do not understand if anyone could help in steps or anything thank you. Solve for A -2(a + 7) = -9

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0
<h2>... Answer is in the pictures above... </h2><h3>... Hope this will help... </h3>

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What are the coordinates of point b on ac such that ab=2/5ac
son4ous [18]

Answer:

(-\frac{36}{7},\frac{40}{7})

Step-by-step explanation:

Coordinates of points A and C are (-8, 6) and (2, 5).

If a point B intersects the segment AB in the ratio of 2 : 5

Then coordinates of the point B will be,

x = \frac{mx_2+nx_1}{m+n}

and y = \frac{my_2+ny_1}{m+n}

where (x_1, y_1) and (x_2,y_2) are the coordinates of the extreme end of the segment and a point divides the segment in the ratio of m : n.

For the coordinates of point B,

x = \frac{2\times 2+(-8)\times 5}{2+5}

  = -\frac{36}{7}

y = \frac{2\times 5+5\times 6}{2+5}

  = \frac{40}{7}

Therefore, coordinates of pint B will be,

(-\frac{36}{7},\frac{40}{7})

3 0
3 years ago
2x - 4 - 6(x + 1) = 5x + 6 a) 8 b) -8/9 c) 4 d) -16/9
andriy [413]
<h2>d) X= - 16/9</h2>

Step-by-step explanation:

2x - 4 - 6(x + 1) = 5x + 6

2x - 4 - 6x - 6 = 5x + 6

2x - 6x - 5x = 4 + 6 + 6

-9x =16

x= -16/9

<em>Hope</em><em> </em><em>this helps</em><em>.</em><em>.</em><em> </em><em>Good</em><em> </em><em>luck</em><em>!</em>

3 0
3 years ago
Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
A pair of integers whose sum is 20
sergij07 [2.7K]

Answer:

10+10

Step-by-step explanation:

when u add them they give you 20 they're integers

7 0
3 years ago
Read 2 more answers
(will give brainliest)<br> 2+5x-3x+6x
pickupchik [31]

Answer:

x = -0.25

Step-by-step explanation:

2+5x-3x+6x

5x-3x+6x = -2

8x = -2

x = -2/8

x = -0.25

3 0
3 years ago
Read 2 more answers
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