Write the equation of the line passing through the points (−2,3) and (−1,−2) in Slope-Intercept and Point-Slope Form.
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Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid =
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid =
Or, The surface area of right regular hexagonal pyramid =
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 ×
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer