The first rectangle has a length of 20cm and a width of 2cm for the area to be 40cm. so, the dimensions must be multiplied by 4 to equal 160cm.
Here s the question this is the doc i put it on please help
The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm
Answer:
The hypotenuse to the nearest tenth is 8.1
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
Let a be the x leg and b be the y leg
a = 7 units
b= 4 units
7^2 + 4^2 = c^2
49+ 16 = c^2
65 = c^2
Take the square root of each side
sqrt(65) = sqrt(c^2)
8.062257748 =c
To the nearest tenth
8.1 =c
Answer:
3(x+22y)
Step-by-step explanation:
Because three can be taken from both of them
