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Lena [83]
3 years ago
11

What are axioms in algebra called in geometry? What are axioms in algebra called in geometry

Mathematics
1 answer:
umka21 [38]3 years ago
5 0

Answer:

Axioms are generally statements made about real numbers. ... Sometimes they are called algebraic postulates. Often what they say about real numbers holds true for geometric figures, and since real numbers are an important part of geometry when it comes to measuring figures, axioms are very useful

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Find the value of x<br> DUE SUNDAY I NEED ASAP
Leto [7]

Answer:

x=43°

Step-by-step explanation:

The angles are adjacent and create a straight line so their sum is 180°.

(x+6)°+(3x+2)°=180°

x°+6°+3x°+2°=180°

4x°+8°=180°

4x°=172°

x=43°

5 0
3 years ago
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CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
Solve the following problems:
siniylev [52]

Answer:

  DB = 13 cm

Step-by-step explanation:

ΔCAB ≅ ΔDBA by ASA, so CA ≅ DB by CPCTC.

CA = 13 cm, so DB = 13 cm.

8 0
3 years ago
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PLEASE HELP LOOK AT THE PICTURE I NEED HELP NOWWWW!!!! WILL GIVE 20 POINTSSSSSS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Verdich [7]

Answer:

A. 35

Step-by-step explanation:

√35 = 5.9160797830996160425673282915616170484155012307943403228797196691

6 0
3 years ago
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What is the length of side BC? What is the length of side GH?
almond37 [142]
In this situation you would have to use ratios to figure it out.
AD over EH or 24/16 that would be equal to 1.5
This would show that BC over GF is also equal to 1.5.
6/4 is equal to 1.5.
Side length BC is 6
6 0
3 years ago
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