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3 years ago

Explain how to use Distributive Property when simplifying an expression

Mathematics

1 answer:

dybincka [34]3 years ago

6 0

Answer:

Expand the equation.

Multiply (distribute) the first numbers of each set, outer numbers of each set, inner numbers of each set, and the last numbers of each set.

Combine like terms.

Solve the equation and simplify, if needed.

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A)0.5<br> B)2.5<br> C)-0.5<br> D)-2.5

7nadin3 [17]

Answer:

B)2.5

Step-by-step explanation:

When x = 3 the actual = 6

Residual = actual - predicted = 6 - 3.5 = 2.5

5 0

3 years ago

Can someone please help me with this

JulsSmile [24]

Answer:

x=155

Step-by-step explanation:

(2x-120)+10=180

or,2x-130=180

or,2x=180+130

or,2x=310

or,x=310÷2

x=155

6 0

2 years ago

Please help me it one question and give explanation because a lot of people lie and make me get wrong:(

Akimi4 [234]

Answer:

Step-by-step explanation:

it doesn't accurately reflect a representation because you still don't know exactly how much the birds and snakes are. you know what they are together but not apart and that's not acceptable

7 0

3 years ago

A college with a graduating class of 4000 students in the year 2010 predicts that its graduating class will grow 5% per year.

anastassius [24]

Hello,

$u_0=4000\\u_1=4000*1.05 (for\ year\ 2011)\\\\u_n=4000*1.05^n\\So:\\year\ 2017: u_7=4000*1.05^7=5628,401690625\ \approx{5628}$

7 0

2 years ago

That's the question ??

Oksanka [162]

Step-by-step explanation:

Before we answer, the area of a Circle given it radius is

$a = \pi r {}^{2}$

The area of a circle given it diameter is

$a = \pi( \frac{d}{2} ) {}^{2}$

So let answers question 1-4.

1. The area is

$1024\pi$

2. The area is

$576\pi$

$1.225\pi$

$309.76\pi$

For the 5th problem, circumference is

$\pi \times d$

where d is the diameter and

$2\pi r$

where r is the radius.

A circumference of 100 m means the radius is 50 because

$2\pi \times r = 100\pi$

$r = 50$

So this means the area is

$2500 {\pi}$

3 0

2 years ago

Explain how to use Distributive Property when simplifying an expression ​

Explain how to use Distributive Property when simplifying an expression