Question

Need help with this math problem

Answer 1

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Step-by-step explanation:

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Taking a bottom-left corner of the graph as (0,0)

Given Line AB,

Point A is located as (4,9)

Point B is located as (16,1)

The slope of AB is

$=\frac{Y1-Y2}{X1-X2}$

$=\frac{9-1}{4-16}$

$=\frac{8}{-12}$

$=\frac{-2}{3}$

The question says "  Draw a line passes through C(13,12) and parallel to Line AB "

Now, Let the equation of the target line is y=mx + c

Where m=slope and c is the y-intercept

The target line is parallel to the line AB

The slope of the Target line = The slope of the Line AB $=\frac{-2}{3}$

m=$=\frac{-2}{3}$

We can write, the equation of the target line is

$y=\frac{-2}{3}x + c$

Also, the Target line is passing through C(13,12)

Point C satisfies the equation

$y=\frac{-2}{3}x + c$

$12=\frac{-2}{3}13 + c$

$12=\frac{-26}{3} + c$

$12+\frac{26}{3}=c$

$c= 12+\frac{26}{3}$

$c= \frac{62}{3}$

Replacing the value

the equation of the target line is

$y=\frac{-2}{3}x + c$

$y=\frac{-2}{3}x + \frac{62}{3}$

$3y= -2x + 62$

It is also asked that if a line is extended , would it passes through the (18,-8)?

If a line passes through the point (18-,8) then, that point must satisfy the equation of a line

the equation of the target line is  $3y= -2x + 62$

$3(-8)= -2(18) + 62$

$(-24)= (-36) + 62$

$(-24)= (-36) + 62$

$(-24)= 26$

Left land side is not equal to right hand side.

Therefore. a line does not pass through the point (18,-8)