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3 years ago

Using the following equation, find the center and radius:

Mathematics

1 answer:

rodikova [14]3 years ago

4 0

Answer: 4) The center is located at (1, 3), and the radius is 6

Step-by-step explanation:

Solve the general equation of the circle.

x^2 -2x +1+ y^2-6y+9= 26+1+9 (x-1)^2+(y-3)^2=36=6^2

Hence, the coordinates of the center (1,3) And the radius will be 6

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Consider a sequence given by the formula f(n) = 1 / 3 ^ n−1 starting with n = 1. Generate the first 5 terms of the

denpristay [2]

Answer:

Step-by-step explanation:

According to the formula we need to start from n = 1. So the first 5 terms of the sequence, will have the following values of n: 1,2,3,4,5

Now, we need to replace the values of n into the formula to get all the terms.

f(1) = 1/3 ^ 1-1 = 1/3^0 = 1.

This is because any number elevated to zero is always the unit, in this case, 1.

f(2) = 1/3 ^2-1 = 1/3 ^1 = 1/3

This, because any number elevated to 1, is always the same initial number.

f(3) = 1/3 ^3-1 = 1/3 ^2 = 1/9.

Because when the exponent is elevating a fraction number, the power goes to both numbers (numerator and denominator)

f(4) = 1/3 ^4-1 = 1/3 ^3 = 1/27.

f(5) = 1/3 ^5-1 = 1/3 ^4 = 1/81.

5 0

4 years ago

A physicist must make sure that the temperature of a metal dies not get colder than -80°C. The physicist changes the metals temp

NeTakaya

The answer is negative 84 because there are to ne

6 0

3 years ago

What is the solution to the proportion? 5/8 = m/40

Triss [41]

Your answer is 25. You do 40 times 5 divided by 8 or 8 times 5 is 40 and 5 times 5 is 25. Hope this helps

4 0

3 years ago

Read 2 more answers

Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d), one of which is co

arlik [135]

A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

$P(C) = \frac{1}{4}$

The probability of choosing wrong answer is

$P(W) = \frac{3}{4}$

Using the multiplication rule
$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

$WWC$

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

$WCW$

Or the first one is correct and the last two are wrong. This will give the arrangement,

$CWW$
.

$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

$P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}$

$P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}$

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

$P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64} \\ \\ P(One \: Correct) = \frac{27}{64}$

7 0

4 years ago

Read 2 more answers

Solve for m. m + 7 ≥ 20 A. m ≥ 27 B. m ≥ 13 C. 13 ≥ m D. 27 ≥ m

diamong [38]

The answer would be C

7 0

3 years ago

Read 2 more answers