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LUCKY_DIMON [66]
3 years ago
14

Select all the ordered pairs that satisfy the function y = 3x -4.

Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

B and D

Step-by-step explanation:

plug in the x and y for the x and y in the equation

if the two sides come out equal to eachother they satify the function

if they dont well they dont satisfy the function

hope this helps <3

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What is 7/6 divided and simplified?
crimeas [40]

Answer:

1 1/6 or 1.16

Step-by-step explanation:

You can find the decimal by dividing 7 by 6 or 7÷6, which equals the answer above, 1.16.

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Where is the picture?

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4 years ago
Que frações equivalentes a 3/4 tem denominador 65
LuckyWell [14K]

Dada fração: 3/4

Necessidade de converter o denominador em 65.

Vamos supor que x deve estar no numerador (topo) das frações para obter 65 no denominador (abaixo) para obter a fração equivalente de 3/4.

Vamos definir uma atribuição.

\frac{3}{4}=\frac{x}{65}

Deixe-nos resolvê-lo por x agora.

Na multiplicação cruzada, obtemos

4x = 195.

Dividindo ambos os lados por 4, obtemos

x = 48.75

Assim, podemos fazer uma fração equivalente de 3/4, colocando 48.75 no topo do denominador 65.

Então, temos \frac{48.75}{68}

7 0
3 years ago
Quadrilateral ACEG≅ Quadrilateral MNPR<br><br> Which statement is true?
saul85 [17]
Line CE is congruent to line NP is the true statement.
4 0
3 years ago
The gypsy moth is a serious threat to oak and aspen trees. A state agriculture department places traps throughout the state to d
k0ka [10]
Part A:

From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is 0.6.



Part B:

The standard deviation is given by the population deviation divided by the square root of the sample size.

standard \ deviation= \frac{\sigma}{\sqrt{n}} = \frac{0.4}{\sqrt{30}} = \frac{0.4}{5.477} =0.073



Part C:

The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by

P(X\ \textgreater \ x)=1-P(X\ \textless \ x) \\  \\ =1-P\left(z\ \textless \  \frac{x-\mu}{\sigma/\sqrt{n}} \right)

Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that <span>the average number of moths in 30 traps is greater than 0.7</span> given by:

P(X\ \textgreater \ 0.7)=1-P(X\ \textless \ 0.7) \\ \\ =1-P\left(z\ \textless \ \frac{0.7-0.6}{0.073} \right)=1-P(z\ \textless \ 1.369) \\  \\ =1-0.91455=\bold{0.0855}
7 0
4 years ago
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