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2 years ago

A line with a slope of 4 passes through the point (2, 1). What is the equation of this line?

Mathematics

1 answer:

olasank [31]2 years ago

7 0

Answer:

point slope form: y - 1 = 4 (x -2)

slope intercept form: y = 4x -7

Step-by-step explanation:

If you want it in point slope form it would be: y - 1 = 4 (x -2)

but if you want it in slope intercept form, you solve this equation

y -1 = 4 (x-2)

y-1 = 4x -8

+1 +1

y = 4x -7 in slope intercept form

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antiseptic1488 [7]

The answer is A, -2x^4 + 6x^2 +3x +4

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2 years ago

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If 1/2 hour Naomi stretches her neck; every 1/3 hour she stretches her legs; and every 1/6 hour she stretches her ams. Which par

allsm [11]

Neck: In 2/3 of an hour Naomi will stretch her neck one (there's not enough time for two neck stretches, that would require an hour).
Legs: In 2/3 of an hour, she will stretch her legs twice (1 stretch every 1/3 of an hour for 2/3 of an hour equals 2).
Arms: In 2/3 of an hour she will stretch her arm four times (2/3 divided by 1/6 equals 4).

Total stretches: 1 neck stretch, 2 legs stretches, and 4 arms stretches.

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3 years ago

Pls answer!! it’s due pls

Volgvan

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2 years ago

Find the area of the composite figure. A=36cm A=40cm A=48cm A=64cm

MissTica

Check the picture below.

so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.

$\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48$

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2 years ago

Find the cosine of angle B.

Alexandra [31]

$\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }$

9² = 12² + 15² - 2 (12) (15) cos (B)

81 = 144 + 225 - 360 cos(B)

81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

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$\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }$

12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

Answer: Cosine Angle A = 3/5

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2 years ago