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kenny6666 [7]
2 years ago
7

The high temperatures (in degrees Fahrenheit) of a random sample of 5 small towns are: 99.6 99.7 97.9 98.6 97.7 Assume high temp

eratures are normally distributed. Based on this data, find the 99% confidence interval of the mean high temperature of towns. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).
Mathematics
1 answer:
mylen [45]2 years ago
5 0

Answer: (97.63, 99.77)

Step-by-step explanation:

Given the data:

99.6 99.7 97.9 98.6 97.7

Using calculator, we can obtain the mean and standard deviation of the sample data:

Mean(m) = 98.7

Standard deviation = 0.93

Sample size (n) = 5

Using the relation to find confidence interval :

Mean ± Zcrit * (s/√n)

Zcrit at 99% = 2.576

98.7 ± 2.576 * (0.93 / √5)

Lower limit : 98.7 - (2.576 * 0.4159086) = 97.6286194464 = 97.63 ( 1 decimal place)

Upper limit : 98.7 + (2.576 * 0.4159086) = 99.7713805536 = 99.77 ( 1 decimal place)

(97.6, 99.8)

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sergiy2304 [10]
You can use this rule

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Possible answers:<br> A) 336cm <br> B) 110m<br> C) 588m<br> D) 1,029m
kozerog [31]

Answer: The area of the enclosure is 1,029 square meters

Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.

If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as

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For the length of the enclosure, we can determine that as follows;

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And for the width,

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3 years ago
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Which is true about the polynomial –8m3 + 11m?
Dima020 [189]

Answer:

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