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2 years ago

Reflect the point (-7, -9) across the x-axis: Then

Mathematics

1 answer:

V125BC [204]2 years ago

8 0

Step-by-step explanation:

Reflecting across the x axis will result in a sign change for. the y component, therefore (-7,-9) becomes (-7,9)

Reflecting across the y axis will result in a sign change for the x component, therefore (-7,-9) becomes (7,-9)

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A student answers 160 of 200 questions on an exam correctly. What percent of the questions did he answer correctly?

Alexandra [31]

Dive correct answers by total questions:

160/200 = 0.80

Multiply by 100 to get percent:

0.80 x 100 = 80%

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3 years ago

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5(3a+b)−2(3a+b) in simplest form<br> I NEED HELP!

nordsb [41]

Answer:

$9a + 3b$

Is the answer

Step-by-step explanation:

$5(3a + b) - 2(3a + b) \\ = 15a + 5b - 6a - 2b \\ = 9a + 3b$

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That is why

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2 years ago

Simplify: 3(4x – 2) + 9 + 2

kirill [66]

Answer:

-6x+5y+8

Step-by-step explanation: subtract 9xfrom 3x

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-6x+5y+10-2

-6x+5y+8

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3 years ago

What is a Formulas? Explain?

maks197457 [2]

Answer:is an expression telling the computer what mathematical operation to perform upon a specific value. When referring to computer software, formulas are most often used in spreadsheet programs, such as Microsoft Excel.

Step-by-step explanation:

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2 years ago

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In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

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2 years ago