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Artyom0805 [142]
3 years ago
9

4x- (1/2)x-7 = 7(1/2)x-7)

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0
All real numbers are solutions.
wolverine [178]3 years ago
8 0

Answer:

answers are Shown below

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Solve this equation: 3x-1/5-2/9x=124/5
Vaselesa [24]
Well, you can only combine the numbers with the variable (the x) in front of them, since there’s no other number on the left side of the equation to combine that lone number with

(example: 3x+2+5x; you can only add 3x and 5x together since 2 has no x).

So 3x and -2/9x would be your answer.
6 0
3 years ago
Consider the linear expression 3x -15
Jobisdone [24]

Answer:

In linear expresiion 3 is the coefficient

X will be the variable and -15 will be the constant term.

5 0
3 years ago
What is the area of ruth's mural?
pentagon [3]

Answer:

Step-by-step explanation:

Comment

The shape consists of a rectangle on the bottom and a trapezoid on the top.

Rectangle

A rectangle has a very simple Area formula. It is Area = L*W. In this case the L = 14 m and is horizontal. The width is at right angles to the length and is marked as 3.

Area = L * w

L = 14

w = 3

Area = 14 * 3 =                            42 m^2

Trapezoid

The trapezoid is a bit more complicated and some things have to be found. First of all b1 is the first base of the trapezoid. It is parallel to and equal to  the Length of the rectangle. b2 is marked 10 meters. The height is just a bit more complicated. The total height of the figure is 8 m. You can't count the 3 m of the rectangle as part of the height because b1 comes only to the top of the rectangle. The height is 8 - 3 = 5

Area = 1/2(b1 + b2)*h/2

b1 = 14

b2 = 10

h = 8 - 3 = 5

Area = 1/2 ( 14 + 10) * 5 / 2

Area = 1/2 (24)*5

Area = 12 * 5

Area =                                      <u>    60 m^2</u>

Total Area                                  102 m^2

8 0
2 years ago
What is the solution to this system of linear equations? 12q + 3r = 15 –4q – 4r = –44 (–18, 29) (–2, 13) (8, –1) (15, –44)
beks73 [17]

Answer:

(-2,13)

I believe this is the answer.

8 0
3 years ago
Read 2 more answers
Rule for raising a power to a new power
KiRa [710]
The practical rule would be, times that number, by the result of the first time you multiplied the first number. But, it would all depend by how much your're raising the number by.

<u>For example:</u> \boxed{4^6}

We do, (4*4*4*4*4*4)= \boxed{\bf{4^6}}= 4096

But, once again, this was an example. This would show and illustrate the rule of "raising a power".<span />
5 0
4 years ago
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