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3 years ago

I only need answer to number 1 btw. My teacher said dont use trig ratios?? so im very lost.

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

It’s 2780 hopes bro ight

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The year the Greek city of Helike disappeared is -1/5 times the year the US civil war ended. Let w represent the year the war en

Lostsunrise [7]

Answer:

ok so

-1/5x=w

w=1865

so -1/5x=1865

x=-9325

Hope This Helps!!!

5 0

2 years ago

Read 2 more answers

30 boxes of melons and 4 melons in each bag . Each bag holds two melons. How melons are there in the store.

SVEN [57.7K]

The answer is the store has 240 melons.
(30x4)x2=240

8 0

3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

What is the remainder when 1,095 is divided by 7?<br> A) 3 <br> B) 4 <br> C) 5 <br> D) 6

Rina8888 [55]

The answer is a or 3

5 0

3 years ago

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Enzo is studying the black bear population at a large national park.

Naddik [55]

Answer:

2,973

Step-by-step explanation:

The black bear population B(t), in the park is modeled by the following function:

$B(t) = 2500 \cdot 2^{0.01t}$

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

$B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973$

There will be 2,973 black bears in 25 years time.

4 0

3 years ago